# Line slope calculator 3x+y=12

**Straight line given by points A[2; 6] and B[3; 3]**

## Calculation:

**Slope-intercept form of line:**y = -3x+12

**Canonical form of the line equation:**3x+y-12 = 0

**Parametric form of the line equation:**

x = t+2

y = -3t+6 ; t ∈ R

**Slope:**m = -3

**Slope angle of line: φ =**-71°33'54″ = -1.249 rad

**X intercept:**x

_{0}= 4

**Y intercept:**y

_{0}= q = 12

**Distance line from the origin:**d

_{0}= 3.7947

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(1; -3)

**Normal vector: n =**(3; 1)

**Midpoint of the segment AB: M =**[2.5; 4.5]

**Perpendicular Bisector equation:**x-3y+11 = 0

**Vector OA = (2; 6) ; |OA| = 6.3246**

**Vector OB = (3; 3) ; |OB| = 4.2426**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**